21x^2-42x+21=0

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Solution for 21x^2-42x+21=0 equation: 



21x^2-42x+21=0

a = 21; b = -42; c = +21;
Δ = b2-4ac
Δ = -422-4·21·21
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{42}{42}=1$

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